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6x^2+30x=576
We move all terms to the left:
6x^2+30x-(576)=0
a = 6; b = 30; c = -576;
Δ = b2-4ac
Δ = 302-4·6·(-576)
Δ = 14724
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{14724}=\sqrt{36*409}=\sqrt{36}*\sqrt{409}=6\sqrt{409}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(30)-6\sqrt{409}}{2*6}=\frac{-30-6\sqrt{409}}{12} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(30)+6\sqrt{409}}{2*6}=\frac{-30+6\sqrt{409}}{12} $
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